Find two consecutive even integers such that twice the smaller is 16 more than the larger.

Question

Mathematics

Casey Chase

14 April, 01:35

Find two consecutive even integers such that twice the smaller is 16 more than the larger.

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Answers (1)

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Bentley Stokes · Answer 1

Answer: smaller: 18; larger: 20

Step-by-step explanation:

Let n be the smaller integer. Then the larger integer is n+2. So:

2n=n+2+16

n=18

The smaller integer is 18; the larger one is 20.