Ask Question
27 May, 09:16

The length and width of a rectangle are measured as 50 cm and 45 cm, respectively, with an error in measurement of at most 0.1 cm in each. Use differentials to estimate the maximum error in the calculated area of the rectangle.

+2
Answers (1)
  1. 27 May, 09:31
    0
    4.5 cm ^ 2

    Step-by-step explanation:

    We have the following partial derivative, knowing that the area is A = x * y:

    dA = (dpA / dpx) * dx + (dpA / dpy) * dy = y * dx + x * dy

    and that | delta x | < = 0.1, | delta and | < = 0.1. We then use dx = 0.1 and dy = 0.1, with x = 50, y = 45;

    So the maximum error in the area would be:

    dA = y * dx + x * dy = 50 * 0.1 + 45 * 0.1 = 5 + 4.5 = 9.5

    In other words, the maximum error is 4.5 cm ^ 2
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The length and width of a rectangle are measured as 50 cm and 45 cm, respectively, with an error in measurement of at most 0.1 cm in each. ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers