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5 August, 04:17

If f (x) = 4x^5+5x^4+1, then what is the remainder when f (x) is divided by x-2

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  1. 5 August, 05:28
    0
    Remainder 209

    Step-by-step explanation:

    f (x) = 4x⁵+5x⁴+1

    x-2=0⇒x=2

    Putting x=2 in the above equation

    f (x) = 4 (2) ⁵ + 5 (2) ⁴+1

    f (x) = 4 (32) + 5 (16) + 1

    f (x) = 128 + 80+1

    f (x) = 209
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