What is the completely factored form of 3x^5-7x^4+6x^2-14x?

x (x - 7) (x^3 + 2)

Step-by-step explanation:

Note that x is a common factor here:

3x^5-7x^4+6x^2-14x = x (3x^4 - 7x^3 + 6x - 14), or:

x (3x^4 - 7x^3 + 6x - 14) Note that 6x - 14 can be rewritten as 2[x - 7]

and that 3x^4 - 7x^3 can be rewritten as x^3[x - 7]

Therefore, x (3x^4 - 7x^3 + 6x - 14 becomes:

x (x - 7) (x^3 + 2)