Ask Question
31 May, 11:52

In an examination 80% students passed. if 15 less have appeared and 10 less have passed, the ratio of passers to failures would have been 5:1. how many students passed and how many appeared in examination?

+2
Answers (1)
  1. 31 May, 14:28
    0
    60 students passed, and 75 appeared in examination.

    Step-by-step explanation:

    Let's say s is the total number of students and p is the number of students who passed.

    80% of the students passed, so:

    0.8 s = p

    If there were 10 less passers, and 15 less students (5 less failures), then the ratio of passers to failures would be 5/1.

    (p - 10) / (s - p - 5) = 5 / 1

    Simplify the second equation:

    p - 10 = 5 (s - p - 5)

    p - 10 = 5s - 5p - 25

    6p = 5s - 15

    Substitute the first equation.

    6 (0.8 s) = 5s - 15

    4.8 s = 5s - 15

    0.2 s = 15

    s = 75

    p = 0.8 s

    p = 60

    60 students passed, and 75 appeared in examination.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “In an examination 80% students passed. if 15 less have appeared and 10 less have passed, the ratio of passers to failures would have been ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers