Y Varies directly as X and inversely as Z. Y=100 when X=5 and Z=10 Find Y when X=3 and Z=60

y = 10

Step-by-step explanation:

based on the question if y varries directly as x

mathematically

y ∝ x

also, y varries inversly as z can be mathematically expressed as

y ∝ 1/z

combining the two expressions

y ∝ x ∝ 1/z

i. e

y = kx/z ... where k is the constant of proportionality

make k the subject of formulae

yz = kx

Divide both sides by x

k = yz/x

when y=100, x = 5 z = 10

k = 100 * 10/5

k = 200

to find y when x = 3 and z = 60

from the equation connecting x, y, z

k = yz/x

200 = 60y/3

cross multiply

60y = 200 * 3

60y = 600

divide both sides by 60

y = 10