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Mathematics
Ronald Anthony
2 February, 03:31
Half angle tan 5pi/8
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Georgia Mathis
2 February, 06:13
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The half-angle formula for tangent is:
tan (a/2) = (sin a / (1 + cos a)) = ((1 - cos a) / sin a)
Now we can plug in values:
tan (5π/8) = (sin (5π/4) / (1 + cos (5π/4)) = ((1 - cos (5π/4)) / sin (5π/4)
tan (5π/8) = (-√2/2) / (1 + (-√2/2)) = (1 - (-√2/2)) / (-√2/2)
tan (5π/8) = ((-√2/2)) / ((2 - √2) / 2) = ((2 + √2) / 2) / (-√2/2)
Now we can solve the first half:
(-√2/2) (2 / (2 - √2))
(-√2/2) ((4 + 2√2) / 2)
(-√2/2) (2 + √2)
(-2√2 - 2) / 2
-√2 - 1
tan (5pi/8) = - √2 - 1
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