If you wish to warm 40 kg of water by 18 ∘C for your bath, find what the quantity of heat is needed. Express your answer in calories cal

Quantity of heat needed (Q) = 722.753 * 10³

Step-by-step explanation:

According to question,

Mass of water (m) = 40 kg

Change in temperature (ΔT) = 18°c

specific heat capacity of water = 4200 j kg^-1 k^-1

The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin.

So, Heat (Q) = m*s*ΔT

Or, Q = 40 kg * 4200 * 18

or, Q = 3024 * 10³ joule

Hence, Quantity of heat needed (Q) = 3024 * 10³ joule

In calories 4.184 joule = 1 calorie

So, 3024 * 10³ joule = 722.753 * 10³