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6 November, 18:35

How much water can a rectangular pool hold if it has a length of 30 feet, a width of 25 feet, and is 8 feet deep?

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Answers (2)
  1. 6 November, 18:47
    0
    44,883 gallons

    Step-by-step explanation:

    The amount of water the pool can hold can be found by calculating the volume of the pool.

    We know that the pool is rectangular, and it is a three dimensional shape (3 dimensions: length, width and depth). Therefore, we can use the formula for finding the volume of a rectangular prism:

    V=l*w*h

    We know the length is 30 feet and the width is 25 feet. The height is also the depth, so the height is 8 feet.

    l = 30 feet

    w=25 feet

    h = 8 feet

    Substitute these values into the formula.

    V = 30 feet * 25 feet * 8 feet

    Multiply the numbers together.

    V = (30 feet * 25 feet) * 8 feet

    V = 750 feet^2 * 8 feet

    V=6000 feet^3

    Now, let's find how many gallons the pool can hold.

    1 ft^3 is equal to 7.4805 gallons. Therefore, we can multiply 6000 ft^3 and 7.4805

    6000 ft^3 * 7.4805 gallons/1 ft^3

    6000 * 7.4805 gallons

    44,883 gallons

    The pool can hold 44,883 gallons of water.
  2. 6 November, 20:29
    0
    44,886 gallons

    Step-by-step explanation:

    We need to find the volume

    V = l*w*h

    V = 30ft*25ft*8ft

    V = 6000 ft^3

    We know that 1 ft^3 = 7.481 gallons

    6000 ft^3 * 7.481 gallons/1 ft^3 = 44886 gallons
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