Find two positive consecutive odd integers whose products is 99.

9,11

Step-by-step explanation:

let the numbers be x, x+2 (since consecutive odd integers have a difference of 2)

therefore;

x (x+2) = 99

x²+2x=99

I usually solve the sum like this,

we need to find the nearest square number (number smaller than the number on the R. H. S)

here, it is 81, whose square root is 9. therefore the solution is 9

verification:

(9) ²+2*9=99

81+18=99

99=99

hence, 9 is the solution. therefore the positive odd consecutive integers are

x=9

x+2=9+2 = 11

verification:

9*11=99

99=99

L. H. S=R. H. S