Write a system of equations with 4,-5 as its solution

x + 2y = 6

3x + 4y = - 8

Step-by-step explanation:

I would start by choosing my coefficients for the 2 equations. I will choose 1 and 2 for the first equation and 3 and 4 for the second equation.

1x + 2y = ?

3x + 4y = ?

Now I need to figure what in on the right-hand side, so I would substitute in 4 for x and - 5 for y.

1 (4) + 2 (-5) = 4 - 10 = - 6, so my first equation would be x + 2y = - 6

3 (4) + 4 (-5) = 12 - 20 = - 8, and my second equation is 3x + 4y = - 8