Ask Question
10 August, 00:33

The length and width of a rectangle are measured as 42 cm and 38 cm, respectively, with an error in measurement of at most 0.1 cm in each. Use differentials to estimate the maximum error in the calculated area of the rectangle.

+3
Answers (1)
  1. 10 August, 04:32
    0
    d (A) = 8 cm²

    Step-by-step explanation:

    Area of a rectangle is:

    A (r) = L * w

    L is the length, and w is the width, then

    d (A) = L * dw + w*dl

    From problem statement we know:

    L = 42 cm w = 38 cm

    With an error in measurement of 0,1 cm in each case, then

    dw = dl = 0,1 cm

    And

    d (A) = 42*0,1 + 38*0,1 ⇒ d (A) = 4.2 + 3.8 ⇒ d (A) = 8 cm²
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The length and width of a rectangle are measured as 42 cm and 38 cm, respectively, with an error in measurement of at most 0.1 cm in each. ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers