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10 December, 18:51

20 different comic books will be distributed to five kids. (a) How many ways are there to distribute the comic books if there are no restrictions on how many go to each kid (other than the fact that all 20 will be given out) ? (b) How many ways are there to distribute the comic books if they are divided evenly so that 4 go to each kid?

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  1. 10 December, 21:59
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    a) 21684

    b) 15504

    Step-by-step explanation:

    a) Distribute the comic books as follows

    only to 1 kid one way but we have five kids then 5

    to two kids C₂₀,₂ = 20! / 2! (20-2) ! = 20*19 / 2 = 190

    To three C₂₀,₃ = 20! / 3! (20 - 3) ! = 20*19*18 / 6 = 1140

    To four C₂₀,₄ = 20! / 4! (20 - 4) ! = 20*19*18*17 / 4*3*2 = 4845

    To five C₂₀,₅ = 20! / 5! (20 - 5) ! = 20*19*18*17*16/5*4*3*2*1

    C₂₀,₅ = 15504

    Then total ways of distribution are:

    5 + 190 + 1140 + 4845 + 15504 = 21684

    b) C₂₀,₅ we know from a that is equal to 15504
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