May rides her bike the same distance that Leah walks. May rides her bike 10 kilometers per hour faster than Leah walks. If it takes may 1 hour and Leah 3 hours to travel that distance, how fast does each travel?

Let x = Leah's speed.

So, rate*time = distance and they are both going the same distance.

Now, we have x*3 = (x + 10) * 1

The left side is Leah's distance and the right side is May's distance. Her rate is x + 10 since she is going to km/h faster than Leah.

So, we solve the equation 3x = x + 10 for x.

Subtracting x from both sides yields: 2x = 10, so x = 5.

Leah's going 5 km/h and May is going 10 faster: 15 km/h