Suppose that y varies directly as the square of x, and that y=567 when x=9. What is y when x=4

y = 112

Step-by-step explanation:

If y varies directly as the square of x

mathematically;

y ∝ x²

y = kx² where 'k' is the constant of proportionality

let u know the value of k for this equation by making k the subject of the formular from y = kx²

divide both sides by x²

k = y / x²

given that y = 567 x = 9

k = 567 / (9) ²

k = 567/81

k = 7

now to get the value of y when x = 4

from the equation conneting x, y,

y = kx²

y = 7 * (4) ²

y = 7 * 16

y = 112