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Today, 00:22

Y=12+2x linear

Y=-16x^2+24x+6 quadratic

If you substitute 12 + 2x for y in the second equation how is the resulting equation written in standard form?

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Answers (2)
  1. Today, 03:46
    0
    The other guys answer is right for the first one but ...

    the second part is : b. 2 (x-1) (8x-3) = 0

    the third part is : (.375, 12.75) and (1, 14)
  2. Today, 04:17
    0
    Answer: B.) 16x^2-22x+6=0
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