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25 October, 03:28

3. The amount of hot chocolate dispensed by a hot chocolate machine is normally distributed with a mean of 16.0 oz and a standard deviation of 2 oz. If the cups hold 18.0 oz, what is the probability that a selected cup will be overfilled

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  1. 25 October, 07:13
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    Answer: the probability that a selected cup will be overfilled is 0.16

    Step-by-step explanation:

    Since amount of hot chocolate dispensed by a hot chocolate machine is normally distributed,

    we would apply the formula for normal distribution which is expressed as

    z = (x - µ) / σ

    Where

    x = amount of hot chocolate dispensed by a hot chocolate machine.

    µ = mean

    σ = standard deviation

    From the information given,

    µ = 16.0 oz

    σ = 2 oz

    We want to find the probability that a selected cup will be overfilled. Since the cup can hold 18.0 oz, the expression would be

    P (x > 18) = 1 - P (x ≤ 18)

    For x = 18,

    z = (18 - 16) / 2 = 1

    Looking at the normal distribution table, the probability corresponding to the z score is 0.84

    P (x > 18) = 1 - 0.84 = 0.16
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