What is the inradius of a triangle with side lengths 9, 40, and 41?

Answer: 20.5

Step-by-step explanation:

From the measure of the length of the sides of the triangle, 9, 40 and 41 we can infer that the triangle is a right angled triangle. 9-40-41 is a Pythagorean triplet.

In a right angled triangle, the circumradius is half the hypotenuse.

In the given triangle, the hypotenuse = 41.

Therefore, the circumradius is 41:2 = 20.5 units.