The pool holds 17,922 gallons of water, and is leaking at a rate of 4 gallons per day. If Mike does not replace the water that has leaked from the pool, how many gallons of water will remain in the pool after 120 days?

Step-by-step explanation:

Water in the pool is leaking at a rate of 4 gallons per day. This rate is linear. It is decreasing in an arithmetic progression. The formula for finding the nth term of an arithmetic progression sequence is

Tn = a + (n-1) d

Where

Tn is the nth term of the sequence

n is the number of terms

d is the common difference

a is the first term of the sequence

From the information given,

The pool holds 17,922 gallons of water initially, so

a = 17922

d = - 4 because it is the rate at which the water is decreasing

n = 120 because we want to determine the number of

gallons of water that will remain in the pool after 120 days.

T120 is the amount that will remain in the pool after 120 days.

T120 = 17922 + (120-1) - 4

T120 = 17922 + 119 * - 4

T120 = 17446 gallons

17442

Step-by-step explanation:

120x4 = 480

17922-480=