The perimeter of a rectangle can be found using the equation P = 2L + 2W, where P is the perimeter, L is the length, and

W is the width of the rectangle. Can the perimeter of the rectangle be 64 units when its width is 11 units and its length is

20 units?

No, that is not possible

Explanation:

P = 2L + 2W

Insert numbers into equation

p = (2) (20) + (2) (11)

Step 1: Simplify both sides of the equation.

p = (2) (20) + (2) (11)

p=40+22

p = (40+22) (Combine Like Terms)

p=62

p=62

The perimeter is 62, not 64, so the perimeter can't be 64 if the length 20 and the width is 11.

Answer:NO

Step-by-step explanation:

P=2L+2w

P=2*20+2*11

P=40+22

P=62