Prove that: - 7 is not the arithmetic square root of 49

Question

Mathematics

Emily Welch

29 May, 06:45

Prove that: - 7 is not the arithmetic square root of 49

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Katelynn Gonzalez · Answer 1

-7 is not the arithmetic square root of 49 only in case we are taking it for natural number.

Step-by-step explanation:

The square root of x is that number which on squaring gives the result as x. For example, the square root of 4 is + 2 or - 2. Because on squaring + 2 or - 2 we get the number 4. Similarly for the case of 49, the square root might be both + 7 or - 7. But if we are taking it as a natural number then - 7 is not valid. Like for length, quantity or other sort of things - 7 is not the arithmetic square root of 49.