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9 June, 17:03

Logan wants to mix an 18% acid solution with a 45% acid solution to get 16L of a 36% acid solution. How many liters of the 18% solution and how many liters of the 45% solution should be mixed?

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  1. 9 June, 17:33
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    Logan needs 5⅓ liters of 18% acid and 10⅔ liters of 45% acid.

    Step-by-step explanation:

    If x is the liters of 18% acid, and y is the liters of 45% acid, then:

    x + y = 16

    0.18x + 0.45y = 0.36 (16)

    Solve the system of equations. Using substitution:

    0.18x + 0.45 (16 - x) = 0.36 (16)

    0.18x + 7.2 - 0.45x = 5.76

    1.44 = 0.27x

    x = 5⅓

    y = 16 - x

    y = 10⅔

    Logan needs 5⅓ liters of 18% acid and 10⅔ liters of 45% acid.
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