Ask Question
30 January, 00:19

Tags are placed to the left leg and right leg of a bear in a forest. Let A1 be the event that the left leg tag is lost and A2 the event that the right leg tag is lost. Suppose these two events are independent and P (A1) = P (A2) =.4. Find the probability that exactly one tag is lost, given that at least one tag is lost.

+4
Answers (1)
  1. 30 January, 03:58
    0
    Answer: 0.51

    Step-by-step explanation:

    Since A1 and A2 are independent so

    P (A1 and A2) = P (A1) P (A2) = 0.3*0.3 = 0.09

    By the addition rule, the probability that at least one leg tag is lost is

    P (A1 or A2) = P (A1) + P (A2) - P (A1 and A2) = 0.3+0.3-0.09 = 0.51
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Tags are placed to the left leg and right leg of a bear in a forest. Let A1 be the event that the left leg tag is lost and A2 the event ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers