Given that f (x) = x^2-4x-3 and g (x) = x+3/4, solve for f (g (x)) when x=9.

f (g (x)) when x=9 would be - 129/4

Step-by-step explanation:

First, you split the parts into two.

f (g (x)) and g (x). * Think of g (x) as the y of f, f (y).

Now you solve for g (x), where you would plug in 9, for the x.

(9) + 3/4 which equals, 39/4.

Now you have solved for g (x), and you have to plug it into the "y" of f.

f (y) = y^2-4y-3

f (39/4) = (39/4) ^2-4 (39/4) - 3

f (39/4) = - 129/4

Your solution should be - 129/4.