Ask Question
13 September, 21:18

Solve sin (2x) cos (6x) - cos (2x) sin (6x) = -0.7

+5
Answers (1)
  1. 14 September, 00:37
    0
    x = π/4 - 1/4 sin^ (-1) (7/10) + (π n_1) / 2 for n_1 element Z

    or x = (π n_2) / 2 + 1/4 sin^ (-1) (7/10) for n_2 element Z

    Step-by-step explanation:

    Solve for x:

    cos (6 x) sin (2 x) - cos (2 x) sin (6 x) = - 0.7

    -0.7 = - 7/10:

    cos (6 x) sin (2 x) - cos (2 x) sin (6 x) = - 7/10

    Reduce trigonometric functions:

    -sin (4 x) = - 7/10

    Multiply both sides by - 1:

    sin (4 x) = 7/10

    Take the inverse sine of both sides:

    4 x = π - sin^ (-1) (7/10) + 2 π n_1 for n_1 element Z

    or 4 x = 2 π n_2 + sin^ (-1) (7/10) for n_2 element Z

    Divide both sides by 4:

    x = π/4 - 1/4 sin^ (-1) (7/10) + (π n_1) / 2 for n_1 element Z

    or 4 x = 2 π n_2 + sin^ (-1) (7/10) for n_2 element Z

    Divide both sides by 4:

    Answer: x = π/4 - 1/4 sin^ (-1) (7/10) + (π n_1) / 2 for n_1 element Z

    or x = (π n_2) / 2 + 1/4 sin^ (-1) (7/10) for n_2 element Z
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Solve sin (2x) cos (6x) - cos (2x) sin (6x) = -0.7 ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers