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14 June, 03:30

For a particular cable, the radius of the base of the inner layer is 2 millimeters (mm) and the radius of the base of the outer layer is 6 mm. What is the percent of the area of the base pf the outer layer is the area of the inner layer?

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  1. 14 June, 07:14
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    Step-by-step explanation:

    The formula for determining the area of a circle is expressed as

    Area = πr²

    Where

    π is a constant whose value is 3.14

    r represents the radius of the circle.

    Considering the inner layer

    radius = 2 millimeters

    Area of base = 3.14 * 2² = 12.56 mm²

    Considering the outer layer,

    Radius = 6 mm

    Area of base = 3.14 * 6² = 113.04 mm²

    Percent of the area of the base of the outer layer that is the area of the base of the inner layer is

    12.56/113.04 * 100 = 11.1%
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