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6 August, 14:04

Solve the system using elimination. 5 x + 4 y = 12 3 x - 3 y = 18

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  1. 6 August, 15:16
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    x = 4, y = - 2

    Step-by-step explanation:

    Solve the following system:

    {5 x + 4 y = 12 | (equation 1)

    3 x - 3 y = 18 | (equation 2)

    Subtract 3/5 * (equation 1) from equation 2:

    {5 x + 4 y = 12 | (equation 1)

    0 x - (27 y) / 5 = 54/5 | (equation 2)

    Multiply equation 2 by 5/27:

    {5 x + 4 y = 12 | (equation 1)

    0 x - y = 2 | (equation 2)

    Multiply equation 2 by - 1:

    {5 x + 4 y = 12 | (equation 1)

    0 x+y = - 2 | (equation 2)

    Subtract 4 * (equation 2) from equation 1:

    {5 x+0 y = 20 | (equation 1)

    0 x+y = - 2 | (equation 2)

    Divide equation 1 by 5:

    {x+0 y = 4 | (equation 1)

    0 x+y = - 2 | (equation 2)

    Collect results:

    Answer: {x = 4, y = - 2
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