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20 January, 20:25

Find the first 3 iterations of the function f (x) = 1/3x+1 if you have an initial value of 2

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  1. 20 January, 20:41
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    5/3, 14/9, 41/27

    Step-by-step explanation:

    f (x) = (⅓) x + 1

    x=0 = 2

    x1 = (⅓) (2) + 1

    = ⅔ + 1

    x1 = 5/3

    x2 = (⅓) (5/3) + 1

    = 5/9 + 1

    x2 = 14/9

    x3 = (⅓) (14/9) + 1

    = 14/27 + 1

    x3 = 41/27
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