Ask Question
9 December, 14:31

Select the correct answer for each statement.

will yield consecutive odd integers.

a. 2k+9, 2k11, 2k+13 or b. 3k+2, 3k+3, 3k+4

will yield consecutive integers.

a. k+1, k+2, k+3 or b. k+6, k+8, k+10

+4
Answers (1)
  1. 9 December, 16:05
    0
    Part A. Option a. is correct

    Part B. Option a. is correct.

    Step-by-step explanation:

    Part A.

    The numbers given by 2k + 9, 2k + 11, 2k + 13 will represent 11, 13 and 15 for k = 1, which are consecutive odd integers.

    And the numbers given by 3k + 2, 3k + 3 and 3k + 4 will represent 5, 6, and 7 for k = 1 and they are not consecutive odd integers.

    Therefore, option a is correct.

    Part B.

    The numbers given by k + 1, k + 2, k + 3 will represent 2, 3 and 4 for k = 1, which are consecutive integers.

    And the numbers given by k + 6, k + 8, and k + 10 will give 7, 9, and 11 for k = 1 and they are not consecutive integers.

    Therefore, option A is correct.

    (Answer)
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Select the correct answer for each statement. will yield consecutive odd integers. a. 2k+9, 2k11, 2k+13 or b. 3k+2, 3k+3, 3k+4 will yield ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers