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17 February, 03:51

Find dydt for the equation below.

7x3+7y3=9

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Answers (2)
  1. 17 February, 04:12
    0
    dy/dt = - x^2/y^2 dx/dt

    Step-by-step explanation:

    7x^3 + 7y^3 = 0

    Take the derivative with respect to t

    7 * 3x^2 dx/dt + 7 * 3y^2 dy/dt = 0

    21 x^2 dx/dt + 21 y^2 dy/dt = 0

    Divide each side by 21

    x^2 dx/dt + y^2 dy/dt = 0

    Subtract x^2 dx/dt from each side

    x^2 dx/dt - x^2 dx/dt+y^2 dy/dt = - x^2 dx/dt

    y^2 dy/dt = - x^2 dx/dt

    Divide each side by y^2

    y^2 / y^2 dy/dt = - x^2/y^2 dx/dt

    dy/dt = - x^2/y^2 dx/dt
  2. 17 February, 04:48
    0
    y=-1

    Step-by-step explanation:

    I thought the unknown space between 7y and 3 was multiplication so here is my work.

    7*3+7y*3

    21+7*-1*3

    =9
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