If f (x) = (1/9) (9^), what is f (3) ?

Given: f (x) = / dfrac{1}{9} (x-2)

We need to find the inverse of f (x).

Step 1: Set f (x) = y

y=/dfrac{1}{9} (x-2)

Step 2: Switch x and y

x=/dfrac{1}{9} (y-2)

Step 3: Solve for y, Isolate y

x=/dfrac{1}{9} (y-2)

Multiply by 9 both sides

9x=y-2

Add 2 both sides

9x+2=y

y=f^{-1} (x)

Hence, f^{-1} (x) = 9x+2