Ask Question
26 September, 23:31

Q1

Find the area of a rectangle whose length and breadth are (x+y) and (x * - xy + y*) respectively.

Q 2

Sum of the digits of a two-digit number is 9. When we

interchange the digits, it is found that the resulting new

number is greater than the original number by 27. What is the two-digit number?

+1
Answers (1)
  1. 27 September, 02:36
    0
    36

    Step-by-step explanation:

    1

    Assuming x = x * and y = y*

    (x+y) (x * - xy + y*) = x² - x²y + xy + xy - xy² + y² = x² - x²y + 2xy - xy² + y²

    Assuming x! = x * and y! = y*

    (x+y) (x * - xy + y*) = xx * - x²y + xy * + x*y - xy² + yy*

    2

    Sum of the digits of a two-digit number is 9.

    Two digits number = xy

    x + y = 9

    When we interchange the digits, it is found that the resulting new

    number is greater than the original number by 27.

    yx = xy + 27

    First find all the pairs of numbers that sum to make 9

    0 + 9

    1 + 8

    2 + 7

    3 + 6

    4 + 5

    Find the difference between the digits in the form xy and yx.

    90 - 09 = 81

    81 - 18 = 63

    72 - 27 = 47

    63 - 36 = 27

    54 - 45 = 9
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Q1 Find the area of a rectangle whose length and breadth are (x+y) and (x * - xy + y*) respectively. Q 2 Sum of the digits of a two-digit ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers