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11 February, 16:19

Where is the removable discontinuity of f (x) located?

x = - 5

F (x) = 5x+10/x^2+7x+10

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Answers (2)
  1. 11 February, 17:39
    0
    The discontinuity of f (x) is at x=25. The denominator goes to zero.
  2. 11 February, 20:00
    0
    F (x) = 0

    Step-by-step explanation:

    5x+10/x^2+7x+10

    When x=-5

    Substitute the value of x in the equation

    5 (-5) + 10 / (-5^2+7 (-5) + 10

    -25+10/25-35+10

    -15/-10+10

    -15/0

    =0
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