Ask Question
23 October, 06:38

The function f/left (x/right) = -/left (x-3/right) ^2+9f (x) = - (x - 3) 2 + 9 can be used to represent the area of a rectangle with a perimeter of 12 units, as a function of the length of the rectangle, xx. What is the maximum area of the rectangle? 12 square units 3 square units 9 square units 6 square units

+1
Answers (1)
  1. 23 October, 06:56
    0
    9 square units

    Step-by-step explanation:

    The area of the rectangle is f (x) = - (x - 3) ² + 9.

    Since this is a parabola, the maximum is at the vertex, (3, 9).
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The function f/left (x/right) = -/left (x-3/right) ^2+9f (x) = - (x - 3) 2 + 9 can be used to represent the area of a rectangle with a ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers