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24 July, 03:02

Simplify the expressions.

i^23

+5
Answers (1)
  1. 24 July, 04:11
    0
    -i

    Step-by-step explanation:

    i^0=1

    i^1=i

    i^2=-1

    i^3=-i

    i^4=1

    This repeats so we want to see how many 4 factors of i there is in i^ (23) which is 5 with a remainder of 3.

    So i^ (23) = i^3=-i.

    i^ (23) = i^ (5*4+3) = (i^4) ^5 * (i^3) = (1) ^5 * (-i) = 1 (-i) = -i.
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