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11 November, 06:43

Write an equation in slope-intercept form for a line that is (a) parallel (b) perpendicular to the line y=-5x-3 and has a y-intercept if 6

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  1. 11 November, 10:35
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    Step-by-step explanation:

    The equation of a straight line can be represented in the slope-intercept form, y = mx + c

    Where c = intercept

    Slope, m = change in value of y on the vertical axis / change in value of x on the horizontal axis

    The given equation is y = - 5x-3

    Compared to y = mx + c, the slope, m is - 5

    a) if two lines are parallel, it means that they have equal slope. Therefore the slope of the line parallel to y = - 5x-3 is - 5. Since the y intercept is 6, the equation would be y = - 5x + 6

    b) if two lines are perpendicular, the slope of one line is the negative reciprocal of the line perpendicular to it. Since the slope of the given line is - 5, the slope of the line perpendicular to it is 1/5. The equation becomes

    y = x/5 + 6
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