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5 February, 13:47

Eight men and eight women have six tickets in one row to the theater. In how many ways can they sit if the first person in the row is a woman and the people alternate woman, man, woman, man and so on?

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  1. 5 February, 16:24
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    As there are six seats in a row and the first person in the row is a woman and the people alternate woman, men, the possibility is

    W

    M

    W

    M

    W

    M

    in that order.

    Now as we four women, three seats for women can be filled in

    X

    4

    P

    3

    =

    24

    ways

    and similarly as we four men, three seats for men can be filled in

    X

    4

    P

    3

    =

    24

    ways

    Hence, total

    24

    *

    24

    =

    576

    permutations.
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