1. Which is an equation of a circle with center (2, - 10) and radius 3? a - (x - 2) 2 + (y + 10) 2 = 3 b - (x - 2) 2 + (y + 10) 2 = 9 c - (x + 10) 2 + (y - 2) 2 = 9 d - (x + 2) 2 + (y - 10) 2 = 3

Question

Mathematics

Sierra Baird

31 May, 05:07

1. Which is an equation of a circle with center (2, - 10) and radius 3? a - (x - 2) 2 + (y + 10) 2 = 3 b - (x - 2) 2 + (y + 10) 2 = 9 c - (x + 10) 2 + (y - 2) 2 = 9 d - (x + 2) 2 + (y - 10) 2 = 3

+3

Answers (1)

Know the Answer?

Issac Mccarthy · Answer 1

B

Step-by-step explanation:

(x-2) ^2 + (y+10) ^2 = 9

as 3 is the radius we always take its square which is 9 so options A and D are not correct.

The equation in general form is like this : (x-a) ^2 + (y-b) ^2 = r^2

hence if x is 2 then equation will be like

(x - 2) ^2 + (y+10) ^2 = 9

if y is - 10 then equation will be

(x-2) ^2 + (y+10) ^2 = 9