Solve the equation 3x + 2 = 4x + 5 using algebra tiles. Which tiles need to be added to both sides to remove the smaller coefficient? 3 positive x-tiles3 negative x-tiles 4 positive x-tiles 4 negative x-tiles Which tiles need to be added to both sides to remove the constant from the right side of the equation? 2 positive unit tiles 2 negative unit tiles 5 positive unit tiles 5 negative unit tiles What is the solution? x = - 3x = - 1x = 3x = 7

Step-by-step explanation:

Given the expression

3x + 2 = 4x + 5

1. The smaller coefficient of x is 3

to remove the smaller coefficient

we need to add - 3x to both sides

3x + 2 + (-3x) = 4x + 5 (-3x)

3x + 2 - 3x = 4x + 5 - 3x

Collecting like terms we have

3x-3x+2 = 4x-3x+5

2 = x + 5

2. The constant on the right side is

5, to remove the constant from the right side of the equation we need to add - 5 to both sides

3x + 2 + ( - 5) = 4x + 5 + (-5)

3x + 2-5 = 4x + 5-5

3x-3 = 4x