2y-3[3-4 (y-5) + 2 (1-3y) ]

Question

Mathematics

Jason Lutz

30 October, 10:43

2y-3[3-4 (y-5) + 2 (1-3y) ]

+1

Answers (2)

Know the Answer?

Skeeter · Answer 1

Step-by-step explanation:

2y-3[3-4 (y-5) + 2 (1-3y) ] = 2y - 3[ 3 - 4*y - (-4) * 5 + 2*1 - 2*3y]

= 2y - 3[ 3 - 4y + 20 + 2 - 6y]

= 2y - 3[ 3+20+2 - 4y-6y] {bring the like terms together}

=2y - 3 [25 - 10y]

=2y - 3*25 - (-3) * 10y

= 2y - 75 + 30y

= 32y - 75

Zoey Hurst · Answer 2

- 75 - 32y

Step-by-step explanation:

2y-3[3-4 (y-5) + 2 (1-3y) ]

= 2y - 3 (3 - 4y + 20 + 2 - 6y)

= 2y - 3 (25 - 10y)

= 2y - 75 - 30y

= - 75 - 32y

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