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2 October, 23:58

What is the standard form of a line with the x intercept of 4 and y intercept of - 2?

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  1. 3 October, 02:27
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    x-2y=4

    Step-by-step explanation:

    So from the question we know the following:

    When something is x intercept it means y=0 so we have (4,0)

    When something is y intercept it means x=0 so we have (0,-2)

    Now you use these to find the slope using the formula m = (y2-y1) / (x2-x1)

    Plug in the values

    m = (-2-0) / 0-4)

    m = (-2/-4)

    m = 1/2

    x-2y=4

    Now you just plug this in slope intercept form y=mx+c, where c is y intercept

    y=1/2 x - 2

    Standard form: ax+by=c

    y=1/2 x - 2 (rearrange to match the above equation)

    -1/2 x + y = -2 (multiply both sides by 2 because we can't have a fraction for a in the standard form)

    -1x+2y=-4 (now multiply both sides by - 1 because a cannot be negative)

    x-2y=4
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