Select one of the factors of x2y3 - 11x2y + 6y2 - 66

We try to factor by maybe grouping

experiment

(x²y³-11x²y) + (6y²-66)

factor

x²y (y²-11) + 6 (y²-11)

undistribute (y²-11) from each

(x²y+6) (y²-11)

we can force a factor out of the 2nd group in the form of a difference of 2 perfect squares

(x²y+6) (y-√11) (y+√11)

either of those 3 are factors