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2 December, 19:06

Solve the system of linear equations below.

2 х + Зу = 2

х + 6 у = 4

А. x = 0, y=2/3

Bх = 2, y = - 2/3

C. х = 4/3, у=2/9

D. x = 4, y = - 2

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Answers (1)
  1. 2 December, 22:16
    0
    The answer is A

    Multiply the 2nd equation by - 2

    -2x - 12y = - 8

    Then add it to the 1st equation

    -9y = - 6

    y = 2/3

    By substituting in the 1st equation

    2x + 3 (2/3) = 2

    2x = 0

    x=0
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