Find the smaller of two consecutive integers X as the sum of the smaller and six times the larger is - 29 write an equation to the Turman the consecutive integers

Step-by-step explanation:

If the number are consecutive, that means they are one after the other, like 1 and 2, or 5 and 6, etc.

If the smaller integer is, say, 1, we have to add 1 to 1 to get to the next integer which is 2. This rule applies for all consecutive integers. That means that the smaller integer will be x, and the larger will be x + 1. Now for our equation.

"The sum of" means we will be adding something, so ___ + ___ and that the sum of these is - 29, so ___ + ___ = - 29. That's a good start.

"The sum of the smaller" is x + ___ = - 29 and

"6 times the larger" is 6 (x + 1) so: x + 6 (x + 1) = - 29.

That's the equation. If you have to solve it, distribute the 6 into the parenthesis to get

x + 6x + 6 = - 29 and

7x + 6 = - 29 and

7x = - 35 so

x = - 5

Since x is the smaller integer, the smaller integer is - 5 and the larger, x + 1, is - 5 + 1 which is - 4.