How much concrete CY is required for a 4 inch thick slab for a building with a 41' x 73' footprint

Question

Mathematics

Spence

14 August, 23:55

How much concrete CY is required for a 4 inch thick slab for a building with a 41' x 73' footprint

+4

Answers (2)

Know the Answer?

Atticus · Answer 1

Just multiply 41' times 73'

Monique Park · Answer 2

Step-by-step explanation:

What is being asked is to find the volume of concrete needed to fill a 41' x 73' area that needs to be 4" tall

' is a foot

" is an inch

First we must build the equation

41' * 73' * 4" = Area

Next, we must set all the values to be equal. We will convert feet to inches.

41' = 492"

73' = 876"

492" * 876" * 4" = Area

Area = 1,734,480" of concrete³ or 144,540' of concrete³

(inches) (feet)