The vertex form of the function

y=x^2+8x+29

Question

Mathematics

Fabian Mitchell

8 May, 11:14

The vertex form of the function

y=x^2+8x+29

+1

Answers (1)

Know the Answer?

Santiago · Answer 1

y = (x+4) ^2 + 13

Step-by-step explanation:

y=x^2+8x+29

To complete the square take the coefficient of the x term

8

Divide by 2

8/2 = 4

Then square it

4^2 = 16

y=x^2+8x+16+13

= (x^2+8x+16) + 13

= (x+4) ^2 + 13

The vertex form of the functiony=x^2+8x+29

The vertex form of the function

y=x^2+8x+29