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7 March, 04:10

In a certain year, the average e-mail user sent or received 143 e-mails each day. The number of e-mails received was 3 more than thrice the number sent. How many were sent and how many were received each day?

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  1. 7 March, 04:33
    0
    35 emails sent 108 emails received in each day.

    Step-by-step explanation:

    Let the number sent = x

    Let the number received = y = 3x + 3

    According to given condition

    x + 3x + 3 = 143

    4x + 3 = 143

    4x = 143 - 3

    4x = 140

    x = 140/4

    x = 35

    y = 3 (35) + 3

    y = 108

    35 emails sent 108 emails received in each day.
  2. 7 March, 04:44
    0
    Each day, 71 mails were sent and 216 mails were received.

    Step-by-step explanation:

    Step 1: Given average mails sent and received is 143. Let the number of sent mails be x. So the number of received mails = 3x + 3. Form an equation out of this, to find x.

    ⇒ Average = (x + 3x + 3) / 2

    ⇒ 143 = 4x + 3/2

    ⇒ 286 = 4x + 3

    ⇒ 4x = 283

    ⇒ x = 70.75 ≈ 71

    and 3x + 3 = 3 * 71 + 3 = 213 + 3 = 216
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