Find the instantaneous rate of change for the function at the given value. f (x) equals x squared plus 3 x at xequalsnegative 3 The instantaneous rate of change at xequalsnegative 3 is nothing.

the instantaneous rate of change of f (x) at x = (-3) is f' (x = (-3)) = (-3)

Step-by-step explanation:

for f (x) = x²+3*x

the rate of change of f (x) is

f' (x) = df (x) / dx = 2x + 3

since the derivative of x² is 2x and the derivative of 3*x is 3.

Then at x = (-3)

f' (x = (-3)) = 2 * (-3) + 3 = (-3)

then the instantaneous rate of change of f (x) at x = (-3) is f' (x = (-3)) = (-3)