The sum of two numbers is 131. One number is 6 more than 4 times the other. Which of the following is the smaller number

Answer: oop

Step-by-step explanation:

Let X = smaller number

Let Y = larger number

Sum of numbers is 130 = => X + Y = 130 = => Y = 130 - X

4 times the smaller subtracted from the larger is 10 = =>

Y - 4*X = 10

Substitute the value for Y in to the 2nd equation

(130 - X) - 4*X = 10

130 - 5*X = 10

-5*X = - 120

X = 24

Y = 130 - 24 = 106

Check: 24 + 106 = 130

106 - 4*24 = 106 - 96 = 10