A rectangular garden is 5ft long, 3ft wife. A second rectangular garden has dimensions that are doubled the dimensions of the first garden. What is the percent of change in perimeter from the first garden to the second garden? The percent increase?% from the first garden to the second garden?

Question

Mathematics

Shyanne Roy

25 May, 11:59

A rectangular garden is 5ft long, 3ft wife. A second rectangular garden has dimensions that are doubled the dimensions of the first garden. What is the percent of change in perimeter from the first garden to the second garden? The percent increase?% from the first garden to the second garden?

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Answers (1)

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Pedro Best · Answer 1

100%

Step-by-step explanation:

Perimeter of first garden is given by 2 (l+w) where l is length and w is width

Perimeter=2 (5+3) = 16

The dimensions of second rectangle is doubled hence 10 ft by 6 ft

Perimeter=2 (10+6) = 32

Change in area will be 32-16=16

Percentage change in area is 16/16*100=100%